Factorise: l²m²n - lm²n² - l²mn²
Solution:
Factorization of an algebraic expression refers to finding out the factors of the given algebraic expression.
In the given expression l²m²n - lm²n² - l²mn²,
The first term l²m²n can be factorised as: l × l × m × m × n
The second term - lm²n² can be factorised as: (-1) × l × m × m × n × n and
The third term - l²mn² can be factorised as: (-1) × l × l × m × n × n
The common factor of all the terms is lmn
Taking out the common factor we get,
l²m²n - lm²n² - l²mn² = lmn(lm - mn - ln)
✦ Try This: Factorise: x³y²z³ - x²y³z³ - x³y³ z²
Given, x³y²z³ - x²y³z³ - x³y³ z²
= x²y²z² [ xz - yz - xy]
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9
NCERT Exemplar Class 8 Maths Chapter 7 Problem 88(iv)
Factorise: l²m²n - lm²n² - l²mn²
Summary:
Factorising l²m²n - lm²n² - l²mn² we get, lmn(lm - mn - ln)
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