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Factorise: ax³ - bx² + cx

Solution:

Factorization of an algebraic expression refers to finding out the factors of the given algebraic expression.

In the given expression ax³ - bx² + cx,

The first term ax³ can be factorized as: a × x × x × x

The second term - bx² can be factorized as:(-1) × b × x × x

The third term cx can be factorized as: c × x

The common factor of all the terms is x

Taking out the common factor we get,

ax³ - bx² + cx = x(ax² - bx + c)

✦ Try This: Factorise: pa³ - qa⁴ - ra⁵

Given, pa³ - qa⁴ - ra⁵

= a³ [p - qa - ra²]

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 88(iii)

Factorise: ax³ - bx² + cx

Summary:

Factorising ax³ - bx² + cx we get x(ax² - bx + c)

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