Factorise the following : 9y² - 66yz + 121z²

Solution:

Given, the polynomial is 9y² - 66yz + 121z² -------------- (1)

We have to factorise the polynomial.

Using the identity,

(a - b)² = a² - 2ab + b² ---------------- (2)

On comparing (1) and (2),

a² = 9y²

a = 3y

b² = 121z²

b = 11z

2ab = 66yz

ab = 33yz

Now, (a + b)² = (3y - 11z)²

Therefore, the factors are (3y - 11z)².

✦ Try This: Factorise the following : 9x² + 6xy + y²

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2

NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 26(ii)

Factorise the following : 9y² - 66yz + 121z²

Summary:

On factorising 9y² - 66yz + 121z² using the algebraic identity we get the factors as (3y - 11z)²

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