Factorise the following : 8p³ + (12/5)p² + (6/25)p + 1/125
Solution:
Given, the expression is 8p³ + (12/5)p² + (6/25)p + 1/125 -------- (1)
We have to factorise the expression.
Using the algebraic identity,
Using algebraic identity,
(a + b)³ = a³ + b³ + 3a²b + 3ab² ------------- (2)
On comparing (1) and (2),
a³ = 8p³
a = 2p
b³ = 1/125
b = 1/5
3a²b = (12/5)p²
a²b = (4/5)p²
3ab² = (6/25)p
ab² = (2/25)p
Here a = 2p and b = 1/5
So, (a + b)³ = (2p + 1/5)³
Therefore, the factors of the given expression are (2p + 1/5), (2p + 1/5) and (2p + 1/5).
✦ Try This: Factorise the following : 27p³ + (27/4)p² + (3/16)p + 1/64
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2
NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 32(ii)
Factorise the following : 8p³ + (12/5)p² + (6/25)p + 1/125
Summary:
On factorising 8p³ + (12/5)p² + (6/25)p + 1/125 we get the factors as (2p + 1/5), (2p + 1/5) and (2p + 1/5)
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