Factorise : 6x² + 7x - 3
Solution:
Given, the polynomial is 6x² + 7x - 3.
We have to factorise the polynomial.
On factoring by splitting the middle term,
6x² + 7x - 3
6x² + 9x - 2x - 3
3x(2x + 3) - 1(2x + 3)
(3x - 1)(2x + 3)
Therefore, the factors are (2x + 3) and (3x - 1).
✦ Try This: Factorise : x² - 6x + 8
Given, the polynomial is x² - 6x + 8.
We have to factorise the polynomial.
On factoring by splitting the middle term,
x² - 6x + 8
x² - 4x - 2x + 8
x(x - 4) - 2(x - 4)
(x - 4)(x - 2)
Therefore, the factors are (x - 4) and (x - 2).
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2
NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 23(ii)
Factorise : 6x² + 7x - 3
Summary:
The general expressions containing variables of varying degrees, coefficients, positive exponents, and constants are known as polynomial functions. On factoring 6x² + 7x - 3 the factors are (2x + 3) and (3x - 1)
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