Factorise: 4xy² - 10x²y + 16x²y² + 2xy
Solution:
Factorization of an algebraic expression refers to finding out the factors of the given algebraic expression.
In the given expression 4xy² - 10x²y + 16x²y² + 2xy,
The first term 4xy² can be factorised as: 2 × 2 × x × y × y
The second term - 10x²y can be factorised as: (-1) × 2 × 5 × x × x × y
The third term 16x²y² can be factorised as: 2 × 2 × 2 × 2 × x × x × y × y and
The fourth term 2xy can be factorised as : 2 × x × y
The common factor of all the terms is 2xy
Taking out the common factor we get,
4xy² - 10x²y + 16x²y² + 2xy = 2xy [2y - 5x + 8xy + 1].
✦ Try This: Factorise: 5x²y² - 10x³y² + 15x²y³ + 25x³y³
Given, 5x²y² - 10x³y² + 15x²y³ + 25x³y³
= 5x²y² [1 - 2x + 3y + 5xy]
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9
NCERT Exemplar Class 8 Maths Chapter 7 Problem 88(vii)
Factorise: 4xy² - 10x²y + 16x²y² + 2xy
Summary:
Factorising 4xy² - 10x²y + 16x²y² + 2xy we get, 2xy [2y - 5x + 8xy + 1]
☛ Related Questions:
visual curriculum