Factorise : 2x² - 7x - 15
Solution:
Given, the polynomial is 2x² - 7x - 15
We have to factorise the polynomial.
On factoring by splitting the middle term,
2x² - 7x - 15
2x² - 10x + 3x - 15
2x(x - 5) + 3(x - 5)
(2x + 3)(x - 5)
Therefore, the factors are (2x + 3) and (x - 5).
✦ Try This: Factorise : x² + 7x - 18
Given, the polynomial is x² + 7x - 18.
We have to factorise the polynomial.
On factoring by splitting the middle term,
x² + 7x - 18
x² + 9x - 2x - 18
x(x + 9) - 2(x + 9)
(x + 9)(x - 2)
Therefore, the factors are (x + 9) and (x - 2).
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2
NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 23(iii)
Factorise : 2x² - 7x - 15
Summary:
The terms of polynomials are defined as the parts of the expression that are separated by the operators "+" or "-". On factoring 2x² + 7x - 15 the factors are (2x + 3) and (x - 5)
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