Factorise: 2a³ - 3a²b + 5ab² - ab
Solution:
Factorization of an algebraic expression refers to finding out the factors of the given algebraic expression.
In the given expression 2a³ - 3a²b + 5ab² - ab,
The first term 2a³ can be factorised as: 2 × a × a × a
The second term - 3a²b can be factorised as: (-1) × 3 × a × a × b
The third term 5ab² can be factorised as: 5 × a × b × b and
The fourth term - ab can be factorised as : (-1) × a × b
The common factor of all the terms is ‘a’
Taking out the common factor we get,
2a³ - 3a²b + 5ab² - ab = a [2a² - 3ab + 5b² - b]
✦ Try This: Factorise: 5x³y² - 7x²y + 7x²y² - 13xy
Given, 5x³y² - 7x²y + 7x²y² - 13xy
= xy [5x²y - 7x + 7xy - 13]
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9
NCERT Exemplar Class 8 Maths Chapter 7 Problem 88(viii)
Factorise: 2a³ - 3a²b + 5ab² - ab
Summary:
Factorising 2a³ - 3a²b + 5ab² - ab we get, a [2a² - 3ab + 5b² - b]
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