Factorise: 24x²yz³ - 6xy³z² + 15x²y²z - 5xyz
Solution:
Factorization of an algebraic expression refers to finding out the factors of the given algebraic expression.
In the given expression 24x²yz³ - 6xy³z² + 15x²y²z - 5xyz,
The first term 24x²yz³ can be factorised as: 2 × 2 × 2 × 3 × x × x × y × z × z × z
The second term - 6xy³z² can be factorised as: (-1) × 2 × 3 × x × y × y × y × z × z
The third term 15x²y²z can be factorised as: 3 × 5 × x × x × y × y × z and
The fourth term - 5xyz can be factorised as : (-1) × 5 × x × y × z
The common factor of all the terms is xyz
Taking out the common factor we get,
24x²yz³ - 6xy³z² + 15x²y²z - 5xyz = xyz [24xz² - 6y²z + 15xy - 5]
✦ Try This: Factorise: 15a²b³c - 30a²b⁵c + 75a²b³c² - 90abc
Given, 15a²b³c - 30a²b⁵c + 75a²b³c² - 90abc
= 15abc[ab² - 2ab⁴ + 5ab²c - 6]
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9
NCERT Exemplar Class 8 Maths Chapter 7 Problem 88(x)
Factorise: 24x²yz³ - 6xy³z² + 15x²y²z - 5xyz
Summary:
Factorising 24x²yz³ - 6xy³z² + 15x²y²z - 5xyz we get xyz [24xz² - 6y²z + 15xy - 5]
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