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Express the following numbers in usual form. 
(i) 3.02×10−6   (ii) 4.5×104   (iii) 3×10−8   (iv) 1.0001×109
(v) 5.8×1012    (vi) 3.61492×106

Solution:

Standard form of exponents is used to represent a very small or large number following a certain set of rules.

The given set of numbers are in standard form. Let's convert them to their usual form as shown below.

(i) 3.02 ×10−6

To convert a smaller number(negative powers of 10) to its usual form shift the decimal towards the left by the number of places equivalent to the power of 10.

3.02 × 10−6 = 3.02/1000000

∴ its usual form is 0.00000302

(ii) 4.5 × 104

To convert a big number(positive powers of 10) to its usual form we need to move the decimal to its right by the number of places equivalent to the power of 10.

4.5 × 104 = 45000

Thus, the usual form is 45000

(iii) 3 × 10−8 = 0.00000003 [Moving the decimal towards the left by 8 places]

(iv) 1.0001 × 109 = 1000100000 [Moving the decimal towards the right by 9 places]

(v) 5.8 × 1012 = 5800000000000 [Moving the decimal towards the right by 12 places]

(vi) 3.61492 × 106 = 3614920 [Moving the decimal towards the right by 6 places]

☛ Check: NCERT Solutions for Class 8 Maths Chapter 12

Video Solution:

Express the following numbers in usual form. (i) 3.02×10⁻⁶ (ii) 4.5×10⁴ (iii) 3×10⁻⁸ (iv) 1.0001×10⁹ (v) 5.8×10¹² (vi) 3.61492×10⁶

Class 8 Maths NCERT Solutions Chapter 12 Exercise 12.2 Question 2

Summary:

The following numbers in usual form (i) 3.02×10−6 (ii) 4.5×104 (iii) 3×10−8 (iv) 1.0001×109 (v) 5.8×1012 (vi) 3.61492×106  are  (i) 0.00000302 (ii) 45000 (iii) 0.00000003 (iv) 1000100000 (v) 5800000000000 and (vi) 3614920 respectively.

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