Express the following numbers in standard form.
(i) 0.0000000000085 (ii) 0.00000000000942
(iii) 6020000000000000 (iv) 0.00000000837
(v) 31860000000
Solution:
Standard form of exponents is used to represent a very small or large number following a certain set of rules.
(i) 0.0000000000085
To convert this small number into the standard form we need to move the decimal to its right by 12 steps.
= 85/10000000000000
= 85/10000000000000
= 8.5 × 10/10¹³
= 8.5 × 10-13 × 10
= 8.5 × 10-12
∴ The standard form of a given number is 8.5 × 10-12
(ii) 0.00000000000942
= 942/100000000000000
= 9.42 × 102 / 1014
= 9.42 × 10−14 × 102
= 9.42 × 10−12
∴ The standard form of a given number is 9.42 × 10−12
(iii) 6020000000000000
= 6.02 × 102 × 10000000000000
= 6.02 × 102 × 1013
= 6.02 × 1015
Decimal has moved by 15 steps towards left.
∴ The standard form of the given number is 6.2 × 1015
(iv) 0.00000000837
= 837 / 100000000000
= 8.37 × 102 / 1011
= 8.37 × 10−11×102
= 8.37 × 10−9
∴ The standard form of a given number is 8.37 × 10−9
(v) 31860000000
31860000000
= 3.186 × 103 × 107
= 3.186 ×1010
So, decimal has moved by 10 steps towards left
∴ The standard form of the given number is 3.186 × 1010
☛ Check: NCERT Solutions for Class 8 Maths Chapter 12
Video Solution:
Express the following numbers in standard form. (i) 0.0000000000085 (ii) 0.00000000000942 (iii) 6020000000000000 (iv) 0.00000000837 (v) 31860000000
Class 8 Maths NCERT Solutions Chapter 12 Exercise 12.2 Question 1
Summary:
The following numbers are expressed in their standard form (i) 0.0000000000085 (ii) 0.00000000000942 (iii) 6020000000000000 (iv) 0.00000000837 (v) 31860000000 as follows (i) 8.5 × 10-12 (ii) 9.42 × 10−12 (iii) 6.02 × 1015 (iv) 8.37 × 10−9 and (v) 3.186 × 1010 respectively.
☛ Related Questions:
- Express the following numbers in usual form. (i) 3.02×10−6 (ii) 4.5×104 (iii) 3×10−8 (iv) 1.0001×109 (v) 5.8×1012 (vi) 3.61492×106
- Express the number appearing in the following statements in standard form. (i) 1 micron is equal to 1/100000 m (ii) Charge of an electron is 0.000,000,000,000,000,000,16 coulomb. (iii) Size of a bacteria is 0.0000005 m (iv) Size of a plant cell is 0.00001275 m (v) Thickness of a thick paper is 0.07 mm
- In a stack there are 5 books each of thickness 20 mm and 5 paper sheets each of thickness 0.016 mm. What is the total thickness of the stack.
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