Expand using suitable identities: (x²y - xy²)²

Solution:

Given, (x²y - xy²)²

Using standard identity: (a - b)² = a² - 2ab + b²

Here, a = x²y and b = xy²

(x²y - xy²)² = (x²y)² - 2(x²y)(xy²) + (xy²)²

= x⁴y² - 2x³y³ + x²y⁴

✦ Try This: Expand using suitable identities: (a³b² - a²b³)²

Given, (a³b² - a²b³)²

Using standard identity: (a - b)² = a² - 2ab + b²

(a³b² - a²b³)² = (a³b²)² - 2(a³b²)(a²b³) + (a²b³)²

= a⁶b⁴ - 2a⁵b⁵ + a⁴b⁶

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 85(ii)

Expand using suitable identities: (x²y - xy²)²

Summary:

Expanding (x²y - xy²)² we get, x⁴y² - 2x³y³ + x²y⁴

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