Expand using suitable identities: [(2a/3) + (b/3)][(2a/3) - (b/3)]

Solution:

Given, [(2a/3) + (b/3)][(2a/3) - (b/3)]

Using standard identity: x² - y² = (x + y) (x - y)

Here x = (2a/3) and y = (b/3)

[(2a/3) + (b/3)][(2a/3) - (b/3)]

= (2a/3)² - (b/3)²

= (4a²/9) - (b²/9)

✦ Try This: Expand using suitable identities: [(4p/5) + (q/2)][(4p/5) - (q/2)]

Given, [(4p/5) + (q/2)][(4p/5) - (q/2)]

Using standard identity: a² - b² = (a + b) (a - b)

[(4p/5) + (q/2)][(4p/5) - (q/2)] = (4p/5)² - (q/2)²

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 85(xi)

Expand using suitable identities: [(2a/3) + (b/3)][(2a/3) - (b/3)]

Summary:

Expanding [(2a/3) +(b/3)][(2a/3) - (b/3)] we get, (4a²/9) - (b²/9)

☛ Related Questions:

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