Expand using suitable identities: [(2/3)x - (3/2)y]²

Solution:

Given, [(2/3)x - (3/2)y]²

Using standard identity: (a - b)² = a² - 2ab + b²

Here, a = (2/3)x and b = (3/2)y

[(2/3)x - (3/2)y]² = [(2/3)x]² - 2[(2/3)x][(3/2)y] + [(3/2)y]²

= (4/9)x² - 2xy + (9/4)y²

✦ Try This: Expand using suitable identities: [(4/7)a + (7/4)b]²

Given, [(4/7)a + (7/4)b]²

Using standard identity: (a + b)² = a² + 2ab + b²

[(4/7)a + (7/4)b]² = [(4/7)a]² + 2[(4/7)a][(7/4)b] + [(7/4)b]²

= (16a²/49) + 2ab + (49b²/16)

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 85(iv)

Expand using suitable identities: [(2/3)x - (3/2)y]²

Summary:

Expanding [(2/3)x - (3/2)y]² we get, (4/9)x² - 2xy + (9/4)y²

☛ Related Questions:

• Expand using suitable identities: [(4/5)p + (5/3)q]²
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• Expand using suitable identities: (2x + 9) (2x - 7)