Encircle the odd one of the following
a. (-9) × 5 × 6 × (-3)
b. 9 × (-5) × 6 × (-3)
c. (-9) × (-5) × (-6) × 3
d. 9 × (-5) × (-6) × 3
Solution:
To encircle the odd one from the given option the easiest and fastest method is to apply integer rules on individual options and examine the pattern that is being followed
a) (-9) × 5 × 6 × (-3) = 810
b) 9 × (-5) × 6 × (-3) = 810
c) (-9) × (-5) × (-6) × 3 = -810
d) 9 × (-5) × (-6) × 3 = 810
Therefore on simplifying the individual option, we examined that, the value of the option (c) (-9) × (-5) × (-6) × 3 = -810 is the odd one out
✦ Try This: Identify the odd one out from the given option: -27 + (-7), -7 - 27, -27 + 7, -27 - 7.
To identify the odd one out from the above-listed option apply integer rules on individual options and examine the pattern that is being followed
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 1
NCERT Exemplar Class 7 Maths Chapter 1 Exercise Problem 28
Encircle the odd one of the following: (-9) × 5 × 6 × (-3), 9 × (-5) × 6 × (-3), (-9) × (-5) × (-6) × 3, 9 × (-5) × (-6) × 3
Summary:
According to properties of integers and after applying integer rules on an individual option we evaluated that, the value of the option (c) (-9) × (-5) × (-6) × 3 = -810 is the odd one out.
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