Draw the graphs of the lines x = -2 and y = 3. Write the vertices of the figure formed by these lines, the x-axis and the y-axis. Also, find the area of the figure
Solution:
The graph of x = -2 is a line parallel to the y-axis at a distance of 2 units to the left of it.
Hence,the line l is the graph of x = -2.
The graph of y = 3 is a line parallel to the x-axis at a distance of 3 units above it.
Hence, the line m is the graph of y = 3.
A is a point on the y-axis at a distance of 3 units above the x-axis.
Thus, the coordinates of A are (0, 3).
C is a point on the x-axis at a distance of 2 units to the left of the y-axis.
Thus, the coordinates of C are (-2, 0).
B is the solution of the pair of equations x = -2 and y = 3.
Thus, the coordinates of B are (-2, 3).
Hence,
The vertices of the rectangle OABC are O (0, 0), A (0, 3), B (-2, 3), C (-2, 0).
The length and breadth of this rectangle are 2 units and 3 units.
Area of a rectangle = length × breadth,
The area of rectangle OABC = 2 × 3
The area of rectangle OABC = 6 sq. units.
Therefore,the area of rectangle OABC = 2 × 3 = 6 sq. units.
✦ Try This: Draw the graphs of the lines x = -3 and y = 4. Write the vertices of the figure formed by these lines, the x-axis and the y-axis. Also, find the area of the figure
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 3
NCERT Exemplar Class 10 Maths Exercise 3.4 Sample Problem 1
Draw the graphs of the lines x = -2 and y = 3. Write the vertices of the figure formed by these lines, the x-axis and the y-axis. Also, find the area of the figure
Summary:
Drawing the graphs of the lines x = -2 and y = 3, the vertices of the rectangle OABC are O (0, 0), A (0, 3), B (-2, 3), C (-2, 0). The area of rectangle OABC = 2 × 3 = 6 sq. units.
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