Draw the graph of the linear equation 3x + 4y = 6. At what points, the graph cuts the x-axis and the y-axis
Solution:
Given, the linear equation is 3x + 4y = 6
We have to draw the graph of the equation and find the points at which the graph cuts the x-axis and the y-axis.
The equation can be rewritten as
4y = 6 - 3x
y = (6 - 3x)/4
When x = 0,
y = (6 - 3(0)) / 4
y = 6/4
y = 3/2
When y = 0
0 = (6 - 3x)/4
6 - 3x = 0
3x = 6
x = 6/3
x = 2
Therefore, the points are (2, 0) and (0, 3/2)
On plotting the points on the graph,
Joining the points, we obtain a straight line which is the graph of the equation 3x + 4y = 6
From the graph, we observe that
The graph cuts the x-axis at the point (2, 0)
The graph cuts the y-axis at the point (0, 3/2)
✦ Try This: Draw the graph of the linear equation 2x + 2y = 8. At what points, the graph of the equation cuts the x-axis and the y-axis?
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 4
NCERT Exemplar Class 9 Maths Exercise 4.4 Problem 3
Draw the graph of the linear equation 3x + 4y = 6. At what points, the graph cuts the x-axis and the y-axis
Summary:
The graph of the linear equation 3x + 4y = 6 is mentioned above. The points at which the graph of the equation cuts the x-axis and the y-axis are (2, 0) and (0, 3/2)
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