Draw the graph of the linear equation 2x + 3y = 12. At what points, the graph of the equation cuts the x-axis and the y-axis
Solution:
Given, the linear equation is 2x + 3y = 12
We have to draw the graph of the equation and find the points at which the graph cuts the x-axis and the y-axis.
The equation can be rewritten as
3y = 12 - 2x
y = (12 - 2x)/3
y = 12/3 - 2x/3
y = 4 - 2x/3
When x = 0,
y = 4 - 2(0)/3
y = 4
When y = 0,
0 = 4 - 2x/3
2x/3 = 4
2x = 12
x = 12/2
x = 6
Therefore, the points are (0, 4) and (6, 0)
On plotting the points on the graph,
Joining the points, we obtain a straight line which is the graph of the equation 2x + 3y = 12
From the graph, we observe that
The graph cuts the x-axis at the point (6, 0)
The graph cuts the y-axis at the point (0, 4)
✦ Try This: Draw the graph of the linear equation x + 2y = 4. At what points, the graph of the equation cuts the x-axis and the y-axis?
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 4
NCERT Exemplar Class 9 Maths Exercise 4.4 Sample Problem 1
Draw the graph of the linear equation 2x + 3y = 12. At what points, the graph of the equation cuts the x-axis and the y-axis
Summary:
The graph of the linear equation 2x + 3y = 12 is mentioned above. The points at which the graph of the equation cuts the x-axis and the y-axis are (6, 0) and (0, 4)
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