Distance between two stations A and B is 690 km. Two cars start simultaneously from A and B towards each other, and the distance between them after 6 hours is 30 km. If the speed of one car is less than the other by 10 km/hr, find the speed of each car.
Solution:
Given, the distance between two stations A and B is 690 km.
Two cars start simultaneously from A and B towards each other.
The distance between the two cars after 6 hours is 30 km.
The speed of one car is less than the other by 10 km/hr.
We have to find the speed of each car.
Let the speed of the faster car be x km/hr.
The speed of other car = (x - 10) km/hr
Let the first car start from point A and the other from point B
Let M and N be the position of the cars after 6 hours.
We know, distance = speed × time
Distance AM = x × 6 = 6x km
Distance BN = (x-10) × 6 = 6x - 60 km
According to the question,
6x + 6x - 60 + 30 = 690
12x = 690 + 30
12x = 720
x = 720/12
x = 60 km/hr
Now, (x - 10) = 60 - 10 = 50 km/hr
Therefore, the speed of the cars are 60 km/hr and 50 km/hr.
✦ Try This: Distance between two stations A and B is 720 km. Two cars start simultaneously from A and B towards each other, and the distance between them after 7 hours is 21 km. If the speed of one car is less than the other by 8 km/hr, find the speed of each car.
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 2
NCERT Exemplar Class 8 Maths Chapter 4 Sample Problem 10
Distance between two stations A and B is 690 km. Two cars start simultaneously from A and B towards each other, and the distance between them after 6 hours is 30 km. If the speed of one car is less than the other by 10 km/hr, find the speed of each car
Summary:
Distance between two stations A and B is 690 km. Two cars start simultaneously from A and B towards each other, and the distance between them after 6 hours is 30 km. If the speed of one car is less than the other by 10 km/hr, the speed of each car is 60 km/hr and 50 km/hr.
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