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Determine, algebraically, the vertices of the triangle formed by the lines, 5x - y = 5, x + 2y = 1 and 6x + y = 17

Solution:

From the above question, we have the equations as,

5x - y = 5 and x + 2y = 1

x + 2y = 1 and 6x + y = 17

5x - y = 5 and 6x + y = 17.

5x - y = 5

x + 2y = 1

x = 1,

y = 0.

Hence, one vertex of the triangle is (1, 0).

Solving the second pair, we get,

x + 2y = 1

6x + y = 17

x = 3,

y = -1.

Hence, another vertex of the triangle is (3, -1).

Solving the third pair, we get,

5x - y = 5

6x + y = 17,

x = 2,

y = 5.

Hence, the third vertex of the triangle is (2, 5).

Therefore,the three vertices of the triangle are (1, 0), (3, -1) and (2, 5).

✦ Try This: Determine, algebraically, the vertices of the triangle formed by the lines, 3x - y = 3, x + y = 1 and 5x + y = 16

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 3

NCERT Exemplar Class 10 Maths Exercise 3.4 Sample Problem 2

Summary:

Algebraically, the three vertices of the triangle formed by the lines 5x - y = 5, x + 2y = 1 and 6x + y = 17 are (1, 0), (3, -1) and (2, 5).

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