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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.

Construct the following quadrilaterals.
(i) Quadrilateral MORE
MO = 6 cm, OR = 4.5 cm
∠M = 60°, ∠O = 105°, ∠R = 105°
(ii) Quadrilateral PLAN
PL = 4 cm, LA = 6.5 cm
∠P = 90°, ∠A = 110°, ∠N = 85°
(iii) Parallelogram HEAR
HE = 5 cm, EA = 6 cm
∠R = 85°
(iv) Rectangle OKAY
OK = 7 cm, KA = 5 cm

Solution:

i) Step 1: Draw a line segment MO= 6 cm.

Step 2: With M as center draw angle of measure 60o.

Step 3: Draw 105º from O.

Step 4: With O as center and radius 4.5 cm draw an arc cutting the ray from O at R. OR = 4.5 cm

Step 5: Construct an angle of 105º from R as above. The ray from R meets the ray from M at a point. Mark the intersection point as E.

Step 6: MORE is the required quadrilateral.

Construct the following quadrilaterals. (i) Quadrilateral MORE MO = 6 cm, OR = 4.5 cm ∠M = 60°, ∠O = 105°, ∠R = 105° (ii) Quadrilateral PLAN PL = 4 cm, LA = 6.5 cm ∠P = 90°, ∠A = 110°, ∠N = 85° (iii) Parallelogram HEAR HE = 5 cm, EA = 6 cm ∠R = 85° (iv) Rectangle OKAY OK = 7 cm, KA = 5 cm

ii) Step 1: Draw a line segment LA = 6.5 cm

Step 2: Draw an angle of 75° at point L and 110° at point A with the help of a protractor.

[∵ 360° – (110° + 90° + 85°) = 75°]

Step 3: Cut LP = 4 cm.

Step 4: Draw an angle of 90° at point P which meets the angle line through point A at point N.

Thus PLAN is the required quadrilateral.

Construct the following quadrilaterals. (i) Quadrilateral MORE MO = 6 cm, OR = 4.5 cm ∠M = 60°, ∠O = 105°, ∠R = 105° (ii) Quadrilateral PLAN PL = 4 cm, LA = 6.5 cm ∠P = 90°, ∠A = 110°, ∠N = 85° (iii) Parallelogram HEAR HE = 5 cm, EA = 6 cm ∠R = 85° (iv) Rectangle OKAY OK = 7 cm, KA = 5 cm

iii) Opposite sides of a parallelogram are equal.

Step 1: Draw a line segment HE = 5 cm.

Step 2: Draw an angle of 85° at E and cut EA = 6 cm.

Step 3: With centre A and radius 5 cm draw an arc.

Step 4: Draw another arc with centre H and radius 6 cm to meet the former arc at R.

Step 5: Join the points HR and AR.

HEAR is the required parallelogram.

Construct the following quadrilaterals. (i) Quadrilateral MORE MO = 6 cm, OR = 4.5 cm ∠M = 60°, ∠O = 105°, ∠R = 105° (ii) Quadrilateral PLAN PL = 4 cm, LA = 6.5 cm ∠P = 90°, ∠A = 110°, ∠N = 85° (iii) Parallelogram HEAR HE = 5 cm, EA = 6 cm ∠R = 85° (iv) Rectangle OKAY OK = 7 cm, KA = 5 cm

iv) All the angles of the rectangle are of 90°.

Step 1: Draw a line segment KO = 7 cm.

Step 2: Draw the angle of 90° at point K and cut KA = 5 cm.

Step 3: With centre O and radius 5 cm draw an arc.

Step 4: Draw another arc with centre A and radius 7 cm to meet the former arc at Y.

Step 5: Join points OY and AY.

OKAY is the required rectangle.

Construct the following quadrilaterals. (i) Quadrilateral MORE MO = 6 cm, OR = 4.5 cm ∠M = 60°, ∠O = 105°, ∠R = 105° (ii) Quadrilateral PLAN PL = 4 cm, LA = 6.5 cm ∠P = 90°, ∠A = 110°, ∠N = 85° (iii) Parallelogram HEAR HE = 5 cm, EA = 6 cm ∠R = 85° (iv) Rectangle OKAY OK = 7 cm, KA = 5 cm

☛ Check: NCERT Solutions for Class 8 Maths Chapter 4

Video Solution:

Construct the following quadrilaterals. (i) Quadrilateral MORE MO = 6 cm, OR = 4.5 cm ∠M = 60°, ∠O = 105°, ∠R = 105° (ii) Quadrilateral PLAN PL = 4 cm, LA = 6.5 cm ∠P = 90°, ∠A = 110°, ∠N = 85° (iii) Parallelogram HEAR HE = 5 cm, EA = 6 cm ∠R = 85° (iv) Rectangle OKAY OK = 7 cm, KA = 5 cm

NCERT Solutions for Class 8 Maths Chapter 4 Exercise 4.3 Question 1

Summary:

The following quadrilaterals are constructed (i) Quadrilateral MORE MO = 6 cm, OR = 4.5 cm ∠M = 60°, ∠O = 105°, ∠R = 105° (ii) Quadrilateral PLAN PL = 4 cm, LA = 6.5 cm ∠P = 90°, ∠A = 110°, ∠N = 85° (iii) Parallelogram HEAR HE = 5 cm, EA = 6 cm ∠R = 85° (iv) Rectangle OKAY OK = 7 cm, KA = 5 cm

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