Construct an equilateral triangle of side 5.5 cm

Solution:

We use the basic rules of construction to solve the question given. We will use scale and compass to do the construction required.

We will draw a rough sketch of ΔABC with the given measures for our reference. This will help us in deciding how to proceed. Then follow the steps given below.

Steps of construction -

1. Draw a line segment BC of length 5.5 cm.
2. From B, we need a point A is at a distance of 5.5cm. So, with B as center, draw an arc of radius 5.5cm (Now A will be somewhere on this arc. Our job is to find where exactly A is).
3. From C, point A is also at a distance of 5.5cm. So, with C as the center, draw an arc of radius 5.5cm (Now A will be somewhere on this arc, we have to fix it).
4. A has to be on both the arcs drawn. So, it is the point of intersection of arcs. Mark the point of intersection of arcs as A
5.  Join AB and AC.
6. Thus, ABC is the required triangle.

☛ Check: Class 7 Maths NCERT Solutions Chapter 10

Video Solution:

Construct an equilateral triangle of side 5.5 cm

Class 7 Maths NCERT Solutions Chapter 10 Exercise 10.2 Question 2

Summary:

An equilateral triangle of side 5.5 cm is constructed.

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