Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°

Solution:

We use the basic rules of construction to solve the question given. 

To construct a ΔABC first, we draw a rough sketch with the given measure such that BC = 7.5 cm, AC = 5 cm, and ∠C = 60° for our reference, then follow the steps given below.

Steps of construction :

1. Draw a line segment BC of length 7.5 cm.
2. At C, draw a ray CX making 60° with BC.
3. With C as the center, draw an arc of radius 5 cm to cut CX at point A.
4. Join AB to get the required triangle.
5. Thus,​​​​​​ ΔABC  is the required triangle.  

☛ Check: NCERT Solutions for Class 7 Maths Chapter 10

Video Solution:

Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°

Class 7 Maths NCERT Solutions Chapter 10 Exercise 10.3 Question 3

Summary:

∆ABC is constructed with BC = 7.5 cm, AC = 5 cm and m∠C = 60°

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