Construct a triangle ABC in which BC = 8cm, ∠B = 45° and AB - AC = 3.5 cm
Solution:
Steps of Construction:
i) Draw base BC = 8cm, and at point, B make an angle CBX of 45° using a protractor.
ii) With B as center and radius BD = 3.5 cm, draw an arc to intersect ray BX at D.
iii) Join DC.
iv) Let's construct a perpendicular bisector of DC. With D and C as the center and radius greater than half of DC, draw arcs above and below the line DC to intersect ray BX at A.
v) Join AC.
ABC is the required triangle.
Verification:
On measuring we see that,
BC = 8cm, ∠B = 45° and AB - AC = 3.5 cm
☛ Check: Class 9 Maths NCERT Solutions Chapter 11
Video Solution:
Construct a triangle ABC in which BC = 8cm, ∠B = 45° and AB - AC = 3.5 cm
Class 9 Maths NCERT Solutions Chapter 11 Exercise 11.2 Question 2
Summary:
It is given that we have to construct a triangle ABC in which BC = 8cm, ∠B = 45° and AB - AC = 3.5 cm. We have drawn the triangle using a compass and ruler and justified the construction.
☛ Related Questions:
- Construct the angles of the following measurements:(i) 30°(ii) 22(1/2)°(iii) 15°
- Construct the following angles and verify by measuring them by a protractor:(i) 75°(ii) 105°(iii) 135°
- Construct an equilateral triangle, given its side and justify the construction.
- Construct a triangle ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm.
visual curriculum