Construct a triangle ABC in which BC = 7.5 cm, ∠B = 45° and AB - AC = 4 cm.

Solution:

Steps of construction

1. Construct a line segment BC = 7.5 cm

2. Construct an angle 45° at B

3. Now mark 4 cm from B and extend BD upto X

4. Join D to C

5. Construct perpendicular bisector PQ on DC

6. Let PQ intersect BX at the point A and join AC

7. So triangle ABC is the required triangle.

Therefore, a triangle ABC is constructed above.

✦ Try This: Construct a triangle ABC in which BC = 6.5 cm, ∠B = 45° and AB - AC = 5 cm.

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 11

NCERT Exemplar Class 9 Maths Exercise 11.3 Sample Problem 1

Construct a triangle ABC in which BC = 7.5 cm, ∠B = 45° and AB - AC = 4 cm.

Summary:

A triangle is a closed shape with 3 angles, 3 sides, and 3 vertices. A triangle ABC in which BC = 7.5 cm, ∠B = 45° and AB - AC = 4 cm is constructed above

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