Construct a triangle ABC in which BC = 5 cm, ∠B = 60° and AC + AB = 7.5 cm.

Solution:

Steps of Construction

1. Construct the base BC = 5 cm

2. Make an ∠XBC = 60° at the point B

3. Now cut the line segment BD which is equal to AC + AB = 7.5 cm from BX ray.

4. Join DC.

5. Let us make ∠DCY = ∠BDC

6. Let the ray CY intersect BX at the point A

7. So triangle ABC is the required triangle.

Therefore, triangle ABC is constructed.

✦ Try This: Construct a triangle ABC in which BC = 6 cm, ∠B = 40° and AC + AB = 8.5 cm.

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 11

NCERT Exemplar Class 9 Maths Exercise 11.3 Problem 5

Construct a triangle ABC in which BC = 5 cm, ∠B = 60° and AC + AB = 7.5 cm.

Summary:

A triangle ABC in which BC = 5 cm, ∠B = 60° and AC + AB = 7.5 cm is constructed above

☛ Related Questions:

• Construct a square of side 3 cm
• Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm
• Construct a rhombus whose side is of length 3.4 cm and one of its angles is 45°