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A day full of math games & activities. Find one near you.
Consider the following frequency distribution:
Class 0-5 6-11 12-17 18-23 24-29
Frequency 13 10 15 8 11
The upper limit of the median class is
a. 17
b. 17.5
c. 18
d. 18.5
Solution:
As the classes are not continuous, we have to make the data continuous by subtracting 0.5 from lower limit and adding 0.5 to the upper limit of each class
Class | Frequency | Cumulative Frequency |
0-5.5 | 13 | 13 |
6.5-11.5 | 10 | 23 |
11.5-17.5 | 15 | 38 |
17.5-23.5 | 8 | 46 |
23.5-29.5 | 11 | 57 |
From the question,
N/2 = 57/2 = 28.5
We know that 28.5 lies between the interval 11.5-17.5
So the upper limit is 17.5
Therefore, the upper limit of the median class is 17.5.
✦ Try This: Consider the following frequency distribution:
Class | 1-5 | 6-10 | 11-15 | 16-20 | 21-25 |
Frequency | 12 | 10 | 5 | 9 | 13 |
The upper limit of the median class is
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 14
NCERT Exemplar Class 10 Maths Exercise 13.1 Problem 7
Consider the following frequency distribution: Class 0-5 6-11 12-17 18-23 24-29 Frequency 13 10 15 8 11. The upper limit of the median class is a. 17, b. 17.5, c. 18, d. 18.5
Summary:
Considering the frequency distribution, the upper limit of the median class is 17.5
☛ Related Questions:
- For the following distribution: Marks Number of students Below 10 3 Below 20 12 Below 30 27 Below 40 . . . .
- Consider the data: Class 65-85 85-105 105-125 125-145 145-165 165-185 185-205 Frequency 4 5 13 20 14 . . . .
- The times, in seconds, taken by 150 athletes to run a 110 m hurdle race are tabulated below: Class 1 . . . .
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