Common factor of 17abc, 34ab², 51a²b is
(a) 17abc
(b) 17ab
(c) 17ac
(d) 17a²b²c

Solution:

Correct option is (b).

Factors of the given expressions are,

(a) 17abc = 17 × a × b × c

(b) 34ab² = 17 × 2 × a × b × b

(c) 51a²b = 17 × a × a × b

Common factor is 17ab.

✦ Try This: Common factor of 15p²q, 3pq², 27p³q³ is (a) 3p, (b) 3q, (c) pq, (d) 3pq

Correct option is (d)

Factors of the given expressions are

(i) 15p²q = 3× 5 × p ×p ×q

(ii) 3pq² = 3× p × q × q

(iii) 27p³q³ = 3 × 3 × 3 × p × p × p × q × q × q

Common factor is 3pq

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

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NCERT Exemplar Class 8 Maths Chapter 7 Problem 17

Common factor of 17abc, 34ab², 51a²b is (a) 17abc, (b) 17ab, (c) 17ac, (d) 17a²b²c

Summary:

Common factor of 17abc, 34ab², 51a²b is 17ab

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