Classify into monomials, binomials and trinomials.
(i) 4y – 7z   (ii) y²   (iii) x + y – xy   (iv) 100
(v) ab – a – b   (vi) 5 – 3t   (vii) 4p²q – 4pq²
(viii) 7mn   (ix) z² – 3z + 8   (x) a² + b²
(xi) z² + z   (xii) 1 + x + x²

Solution:

Monomial are the expressions having a single term in the most simplified form.

Binomials are expressions having exactly two terms in the most simplified form.

Trinomials are expressions having exactly three terms in the most simplified form.

Classifying the given expressions into monomials, binomials, and trinomials.

(i) 4y – 7z : Binomial.

(ii) y² : Monomial.

(iii) x + y – xy : Trinomial.

(iv) 100 : Monomial.

(v) ab – a – b : Trinomial

(vi) 5 – 3t : Binomial

(vii) 4p²q – 4pq² : Binomial

(viii) 7mn : Monomial.

(ix) z² – 3z + 8 : Trinomial

(x) a² + b² : Binomial

(xi) z² + z : Binomial

(xii) 1 + x + x² : Trinomial

☛ Check: NCERT Solutions for Class 7 Maths Chapter 12

Video Solution:

Classify into monomials, binomials and trinomials: (i) 4y – 7z (ii) y² (iii) x + y – xy (iv) 100 (v) ab – a – b (vi) 5 – 3t (vii) 4p²q – 4pq² (viii) 7mn (ix) z² – 3z + 8 (x) a² + b² (xi) z² + z (xii) 1 + x + x²

Maths NCERT Solutions Class 7 Chapter 12 Exercise 12.1 Question 5

Summary:

The following are classified into monomials, binomials and trinomials: (i) 4y – 7z : Binomial. (ii) y² : Monomial. (iii) x + y – xy : Trinomial. (iv) 100 : Monomial. (v) ab – a – b : Trinomial (vi) 5 – 3t : Binomial (vii) 4p²q – 4pq² : Binomial (viii) 7mn : Monomial. (ix) z² – 3z + 8 : Trinomial (x) a² + b² : Binomial (xi) z² + z : Binomial (xii) 1 + x + x² : Trinomial

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