Check whether p(x) is a multiple of g(x) or not : p(x) = x³ - 5x² + 4x - 3, g(x) = x - 2
Solution:
Given, p(x) = x³ - 5x² + 4x - 3
Also, g(x) = x - 2
We have to check whether p(x) is a multiple of g(x) or not.
We know that if p(x) is a multiple of g(x) then g(x) must be divisible by p(x)
Let g(x) = 0
x - 2 = 0
x = 2
Put x = 2 in p(x)
p(2) = (2)³ - 5(2)² + 4(2) - 3
= 8 - 5(4) + 8 - 3
= 8 - 20 + 5
= 13 - 20
= -7
p(x) ≠ 0
Since the remainder is not zero, g(x) is not divisible by p(x)
Therefore, p(x) is not a multiple of g(x).
✦ Try This: Check whether p(x) is a multiple of g(x) or not, where p(x) = 3x³ + 3x + 9, g(x) = x - 3
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2
NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 15(i)
Check whether p(x) is a multiple of g(x) or not : p(x) = x³ - 5x² + 4x - 3, g(x) = x - 2
Summary:
p(x) is not a multiple of g(x) or not, where p(x) = x³ - 5x² + 4x - 3, g(x) = x - 2 since p(x) ≠ 0 when x = 2
☛ Related Questions:
visual curriculum