Check whether g(x) is a factor of p(x) or not, where p(x) = 8x³ - 6x² - 4x + 3, g(x) = x/3 - 1/4

Solution:

Given, p(x) = 8x³ - 6x² - 4x + 3

Also, g(x) = x/3 - 1/4

We have to check whether g(x) is a factor of p(x) or not.

Let g(x) = 0

x/3 - 1/4 = 0

x/3 = 1/4

x = 3/4

Put x = 3/4 in p(x)

p(3/4) = 8(3/4)³ - 6(3/4)² - 4(3/4) + 3

= 8(27/64) - 6(9/16) - 3 + 3

= 27/8 - 3(9/8)

= 27/8 - 27/8

= 0

p(x) = 0

Therefore, g(x) is a factor of p(x).

✦ Try This: Check whether g(x) is a factor of p(x) or not, where p(x) = 4x³ - 3x + 1, g(x) = 2x + 3

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2

NCERT Exemplar Class 9 Maths Exercise 2.3 Sample Problem 1(ii)

Check whether g(x) is a factor of p(x) or not, where p(x) = 8x³ - 6x² - 4x + 3, g(x) = x/3 - 1/4

Summary:

A factor is a number that divides another number evenly, that is with no remainder. g(x) is a factor of p(x), where p(x) = 8x³ - 6x² - 4x + 3, g(x) = x/3 - 1/4

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