Carry out the following divisions
(i) 28x4 ÷ 56x (ii) -36 y3 ÷ 9 y2 (iii) 66 pq2r3 ÷ 11qr2
(iv) 34x3y3z3 ÷ 51xy2 z3 (v) 12a8b8 ÷ (-6a6b4 )
Solution:
We will be finding out factors of the expressions and then cancel out common factors of the numerator and the denominator.
(i) 28x4 ÷ 56x
28x4 can be written as 2 × 2 × 7 × x × x × x × x and
56x can be written as 2 × 2 × 2 × 7 × x
Then, 28x4 ÷ 56x = (2 × 2 × 7 × x × x × x × x) / (2 × 2 × 2 × 7 × x)
= x3/2
(ii) - 36y3 ÷ 9y2
-36y3 can be written as and - 2 × 2 × 3 × 3 × y × y × y and
9y2 can be written as 3 × 3 × y × y
Then, -36y3 ÷ 9y2 = (-2 × 2 × 3 × 3 × y × y × y) / (3 × 3 × y × y)
= -4y
(iii) 66 pq2r3 ÷ 11qr2
66pq2r3 can be written as 2 × 3 × 11 × p × q × q × r × r × r and
11qr2 can be written as 11 × q × r × r
Then, 66 pq2r3 ÷ 11qr2 = (2 × 3 × 11 × p × q × q × r × r × r) / (11 × q × r × r)
= 6pqr
(iv) 34x3y3z3 ÷ 51xy2z3
34x3y3z3 can be written as 2 × 17 × x × x × x × y × y × y × z × z × z and
51xy2z3 can be written as 3 × 17 × x × y × y × z × z × z
Then, 34x3y3z3 ÷ 51xy2z3 = (2 × 17 × x × x × x × y × y × y × z × z × z) /(3 × 17 × x × y × y × z × z × z)
= 2x2y / 3
(v) 12a8b8 ÷ (-6a6b4)
12a8b8 can be written as 2 × 2 × 3 × a8 × b8 and
-6a6b4 can be written as -2 × 3 × a6 × b4
Then, 12a8b8 ÷ (-6a6b4) = (2 × 2 × 3 × a8 × b8) / (-2 × 3 × a6 × b4)
= -2a2b4
☛ Check: NCERT Solutions for Class 8 Maths Chapter 14
Video Solution:
Carry out the following divisions. (i) 28x⁴ ÷ 56x (ii) -36 y³ ÷ 9 y² (iii) 66 pq²r³ ÷ 11qr² (iv) 34x³y³z³ ÷ 51xy² z³ (v) 12a⁸b⁸ ÷ (-6a⁶b⁴ )
Class 8 Maths NCERT Solutions Chapter 14 Exercise 14.3 Question 1
Summary:
The following divisions are carried out (i) 28x4 ÷ 56x (ii) -36 y3 ÷ 9 y2 (iii) 66 pq2r3 ÷ 11qr2 (iv) 34x3y3z3 ÷ 51xy2 z3 (v) 12a8b8 ÷ (-6a6b4 ) and the result is as follows (i)x3/2 (ii) -4y (iii) 6pqr (iv) 2x2y / 3 (v) -2a2b4
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