Can the quadratic polynomial x² + kx + k have equal zeroes for some odd integer k > 1
Solution:
Given, the quadratic polynomial is x² + kx + k
We have to find whether the zeros of the polynomial are equal for some odd integer k > 1
Assuming the zeros of the polynomial are equal,
The value of the discriminant will be equal to zero.
Discriminant = b² - 4ac
b² - 4ac = 0
b² = 4ac
Here, a = 1, b = k and c = k
(k)² - 4(1)(k) = 0
k² - 4k = 0
k(k - 4) = 0
So, k = 0 or k = 4.
The quadratic polynomial will have equal zeros at k = 0 and k = 4
Therefore, the quadratic polynomial cannot have equal zeros for any odd integer k > 1
✦ Try This: Can the quadratic polynomial x² + ax + a have equal zeroes for some odd integer a > 1
Given, the quadratic polynomial is x² + ax + a
We have to find whether the zeros of the polynomial are equal for some odd integer a > 1
Assuming the zeros of the polynomial are equal,
The value of the discriminant will be equal to zero.
Discriminant = b² - 4ac
b² - 4ac = 0
b² = 4ac
Here, a = 1, b = a and c = a
a.² - 4(1)a. = 0
a² - 4a = 0
a(a - 4) = 0
So, a = 0 or a = 4.
The quadratic polynomial will have equal zeros at a = 0 and a = 4.
Therefore, the quadratic polynomial cannot have equal zeros for any odd integer a > 1
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 2
NCERT Exemplar Class 10 Maths Exercise 2.2 Problem 1 (v)
Can the quadratic polynomial x² + kx + k have equal zeroes for some odd integer k > 1
Summary:
The quadratic polynomial x² + kx + k has equal zeroes for some odd integer k > 1.Hence the statement is false.
☛ Related Questions:
- If the graph of a polynomial intersects the x-axis at only one point, it cannot be a quadratic polyn . . . .
- If the graph of a polynomial intersects the x-axis at exactly two points, it need not be a quadratic . . . .
- If two of the zeroes of a cubic polynomial are zero, then it does not have linear and constant terms . . . .
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