By selling 50 pens, a shopkeeper lost the amount equal to the selling price of 10 pens. His loss per cent is __________
Solution :
Let the selling price(SP) of each pen be x. Therefore the selling price of 50 pens will be :
Selling Price of 50 pens = 50x
By selling at x the shopkeeper makes a loss of selling price of 10 pens which is equal to :
Loss made by selling 50 pens for x = 10x
Therefore,
SP of 50 pens - CP of 50 pens = Selling price of 10 pens
Since it is a loss we can write:
50x - CP = -10x
Therefore Cost Price(CP) of 50 pens = 50x + 10x = 60x
Loss % = [(SP - CP)/CP] × 100
= [(50x - 60x)/60x] × 100
= [10x/60x] × 100
= (1/6) × 100
= 50/3%
✦ Try this: By selling 60 pens, a shopkeeper lost the amount equal to the selling price of 15 pens. His loss per cent is __________.
If selling price of a pen is x then the loss on selling 60 pens is 15x
Loss = SP of 60 pens - Cost Price of 60 Pens = -(SP of 15 pens)
CP of 60 pens = SP of 60 pens + SP of 15 pens
= 60x + 15x = 75x
Loss % = [15x/75x] × 100 = 20%
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 8
NCERT Exemplar Class 8 Maths Chapter 9 Sample Problem 5
By selling 50 pens, a shopkeeper lost the amount equal to the selling price of 10 pens. His loss per cent is __________
Summary:
By selling 50 pens, a shopkeeper lost the amount equal the selling price of 10 pens. His loss percent is 50/3%
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