By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x³ - 6x² + 2x - 4, g(x) = 1 - 3x/2
Solution:
Given, p(x) = x³ - 6x² + 2x - 4
g(x) = 1 - 3x/2
We have to find the remainder by remainder theorem when p(x) is divided by g(x).
The remainder theorem states that when a polynomial f(x) is divided by a linear polynomial , x - a, the remainder of that division will be equivalent to f(a).
Let g(x) = 0
1 - 3x/2 = 0
3x/2 = 1
x = 2/3
Substitute x = 2/3 in p(x) to get the remainder,
p(3) = (2/3)³ - 6(2/3)² + 2(2/3) - 4
= 8/27 - 6(4/9) + 4/3 - 4
= (8 - 24(3) + 4(9) - 4(27))/27
= (8 - 72 + 36 - 108)/27
= -136/27
Therefore, the remainder is -136/27.
✦ Try This: By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x³ + 6x² - 10x - 3, g(x) = x + 2
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2
NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 14(iv)
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x³ - 6x² + 2x - 4, g(x) = 1 - 3x/2
Summary:
By Remainder Theorem the remainder, when p(x) is divided by g(x), where p(x) = x³ - 6x² + 2x - 4, g(x) = 1 - 3x/2 is -136/27
☛ Related Questions:
visual curriculum