By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x³ - 3x² + 4x + 50, g(x) = x - 3

Solution:

Given, p(x) = x³ - 3x² + 4x + 50

g(x) = x - 3

We have to find the remainder by remainder theorem when p(x) is divided by g(x).

The remainder theorem states that when a polynomial f(x) is divided by a linear polynomial , x - a, the remainder of that division will be equivalent to f(a).

Let g(x) = 0

x - 3 = 0

x = 3

Substitute x = 3 in p(x) to get the remainder,

p(3) = (3)³ - 3(3)² + 4(3) + 50

= 27 - 3(9) + 12 + 50

= 27 - 27 + 62

= 62

Therefore, the remainder is 62.

✦ Try This: By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = 3x³ + x² - x - 3, g(x) = x - 2

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2

NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 14(ii)

By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x³ - 3x² + 4x + 50, g(x) = x - 3

Summary:

By Remainder Theorem the remainder, when p(x) is divided by g(x), where p(x) = x³ - 3x² + 4x + 50, g(x) = x - 3 is 62

☛ Related Questions:

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• By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x³ - 6x² + 2x - . . . .
• Check whether p(x) is a multiple of g(x) or not : p(x) = x³ - 5x² + 4x - 3, g(x) = x - 2