By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial : x⁴ + 1; x - 1
Solution:
Given, the first polynomial is x⁴ + 1
The second polynomial is x - 1.
We have to find the quotient and the remainder by actual division when the first polynomial is divided by the second polynomial.
The first polynomial can be written as x⁴ + 0x³ + 0x² + x + 1
By actual division,
Therefore, the quotient is x³ + x² + x + 1 and the remainder is 2.
✦ Try This: By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial : x⁴ + 2x; x - 2
Find the zeroes of the polynomial : p(x) = (x - 2)² - (x + 2)²
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2
NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 13
By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial : x⁴ + 1; x - 1
Summary:
By actual division, the quotient and the remainder when the first polynomial is divided by the second polynomial : x⁴ + 1; x - 1 are x³ + x² + x + 1 and 2
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