Both x and y vary directly with each other and when x is 10, y is 14, which of the following is not a possible pair of corresponding values of x and y
(a) 25 and 35
(b) 35 and 25
(c) 35 and 49
(d) 15 and 21
Solution:
Given that x = 10 and y = 14 then as per the rule of direct proportion we have:
x/y = k
Where k = constant of proportionality
k = 10/14
k = 5/7
Verifying the alternatives given above we have:
(a) 25/35 = 5/7
(b) 35/25 = 7/5
(c) 35/49 = 5/7
(d) 15/21 = 5/7
Hence the pair which does not give the proportionality constant k = 5/7 is 35 and 25
✦ Try This: Both x and y vary inversely with each other and when x is 5, y is 4, which of the following is a possible pair of corresponding values of x and y? (a) 10 and 2, (b) 7 and 3, (c) 4 and 8, (d) 5 and 6
Given that x = 5 and y = 4 then as per the rule of direct proportion we have:
x ∝ 1/y
Which means
xy = k
Where k = constant of proportionality
k = 5 × 4
k = 20
Verifying the alternatives given above we have:
(a) 10 × 2 = 20
(b) 7 × 3 = 21
(c) 4 × 8 = 32
(d) 5 × 6 = 30
Hence the pair which gives the proportionality constant k = 20 is 10 and 2
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 13
NCERT Exemplar Class 8 Maths Chapter 10 Problem 16
Both x and y vary directly with each other and when x is 10, y is 14, which of the following is not a possible pair of corresponding values of x and y (a) 25 and 35, (b) 35 and 25, (c) 35 and 49, (d) 15 and 21
Summary:
Both x and y vary directly with each other and when x is 10, y is 14, the pair which does not correspond to the pair of x = 10 and y = 14 is (35 and 25)
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