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Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Solution:

Let the age of Baichung be x years.

Age of Baichung’s father = x + 29

Age of Baichung’s grandfather = Age of Baichung's father + 26 = x + 29 + 26 = x + 55

Sum of ages of all the three is 135 years (Given)

Banichung's age + Baichung's father's age + Baichung's granfather's age = 135

⇒ x + (x + 29) + (x + 55) = 135

⇒ 3x + 84 = 135

⇒ 3x = 135 - 84

⇒ 3x = 51

⇒ x = 51/3

⇒ x = 17

Thus, we get the ages of each of them as

Age of Baichung = 17 years

Age of Baichung’s father = x + 29 = 17 + 29 = 46 years

Age of Baichung’s grandfather = x + 55 = 17 + 55 = 72 years

☛ Check: NCERT Solutions for Class 8 Maths Chapter 2

Video Solution:

Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

NCERT Solutions Class 8 Maths Chapter 2 Exercise 2.2 Question 11

Summary:

Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. The ages of Baichung, his father, and grandfather are 17, 46, and 72 years respectively.

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