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At what point does the graph of the linear equation x + y = 5 meet a line which is parallel to the y-axis, at a distance 2 units from the origin and in the positive direction of x-axis

Solution:

Given, the linear equation is x + y = 5

We have to find the point at which the equation meets a line parallel to the y-axis at a distance of 2 units from the origin and in the positive direction of the x-axis.

The coordinates of the point lying on the line parallel to the y-axis, at a distance x units from the origin and in the positive direction of the x-axis is given by (x, a)

Now, the distance x = 2 units

So, the coordinates of the point = (2, a)

Now put x = 2 and y = a in the given equation,

2 + a = 5

a = 5 - 2

a = 3

Therefore, the point is (2, 3)

✦ Try This: At what point does the graph of the linear equation x + y = 7 meet a line which is parallel to the y-axis, at a distance 4 units from the origin and in the positive direction of x-axis.

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 4

NCERT Exemplar Class 9 Maths Exercise 4.3 Sample Problem 2

At what point does the graph of the linear equation x + y = 5 meet a line which is parallel to the y-axis, at a distance 2 units from the origin and in the positive direction of x-axis

Summary:

The point at which the equation meets a line parallel to the y-axis at a distance of 2 units from the origin and in the positive direction of the x-axis is (2, 3)

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