Arrange the rational numbers -7/10, 5/-8, 2/-3, -1/4, -3/5 in ascending order.
Solution:
Given, the rational numbers are -7/10, 5/-8, 2/-3, -1/4 and -3/5.
We have to arrange the rational numbers in ascending order.
Taking LCM of 10, 8, 3, 4 and 5,
10 = 2 × 5
8 = 2 × 2 × 2
3 = 3
4 = 2 × 2
5 = 5
LCM = 2 × 2 × 2 × 5 × 3 = 120
If the numerator and denominator of a rational number are multiplied or divided by a non-zero integer, we get a rational number which is said to be equivalent to the given rational number.
-7/10 = (-7) × 12 / 10 × 12 = -84/120
5/-8 = 5 × 15 / (-8) × 15 = -75/120
2/-3 = 2 × 40 / (-3) × 40 = -80/120
-1/4 = (-1) × 30 / 4 × 30 = -30/120
-3/5 = (-3) × 24 / 5 × 24 = -72/120
The rational numbers are -84/120, -75/120, -80/120, -30/120 and -72/120
On arranging the numbers in ascending order,
-84/120, -80/120, -75/120, -72/120 and -30/120
Therefore, -7/10 < -2/3 < -5/8 < -3/5 < -1/4
✦ Try This: Arrange the rational numbers 2/5, 7/10, 8/15, 13/30 in ascending order.
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 9
NCERT Exemplar Class 7 Maths Chapter 8 Problem 72
Arrange the rational numbers -7/10, 5/-8, 2/-3, -1/4, -3/5 in ascending order.
Summary:
On arranging the rational numbers -7/10, 5/-8, 2/-3, -1/4, -3/5 in ascending order, we get -7/10 < -2/3 < -5/8 < -3/5 < -1/4
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