AOBC is a rectangle whose three vertices are vertices A (0, 3), O (0, 0) and B (5, 0). The length of its diagonal is
a. 5
b. 3
c. √34
d. 4

Solution:

It is given that

AOBC is a rectangle whose three vertices are vertices A (0, 3), O (0, 0) and B (5, 0)

Length of diagonal AB is the distance between the points (0,3) and (5,0)

We know that the formula to find the distance between two points P(x₁, y₁) and Q(x₂, y₂) is

\(Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\)

Distance between the points (0,3) and (5,0) can be found by

\(Distance=\sqrt{(5-0)^{2}+(0 - 3)^{2}}\)

So we get

Distance between the points = √(25 + 9) = √34

Distance between the points = √34 units

Therefore, the length of its diagonal is √34 units.

✦ Try This: PORS is a rectangle whose three vertices are vertices P (0, 2), O (0, 0) and R (4, 0). The length of its diagonal is

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 7

NCERT Exemplar Class 10 Maths Exercise 7.1 Problem 5

AOBC is a rectangle whose three vertices are vertices A (0, 3), O (0, 0) and B (5, 0). The length of its diagonal is a. 5, b. 3, c. √34, d. 4

Summary:

AOBC is a rectangle whose three vertices are vertices A (0, 3), O (0, 0) and B (5, 0). The length of its diagonal is √34 units

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