A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
Aman’s age is three times his son’s age. Ten years ago he was five times his son’s age. Find their present ages
Solution:
Let's form a linear equation for the given problem statement.
Let Aman’s son’s age be x years.
Therefore, Aman’s age will be 3x years.
Ten years ago, their age was (x - 10) years and (3x - 10) years respectively.
According to the question,10 years ago,
Aman’s age = 5 × Aman’s son’s age 10 years ago
3x - 10 = 5(x - 10)
3x - 10 = 5x - 50
2x = 40
x = 20 and 3x = 60
Therefore, Aman and his son's age are 60 and 20 years respectively.
☛ Check: Class 8 Maths NCERT Solutions Chapter 2
Video Solution:
Aman’s age is three times his son’s age. Ten years ago he was five times his son’s age. Find their present ages
NCERT Solutions Class 8 Maths Chapter 2 Exercise 2.4 Question 10
Summary:
Aman’s age is three times his son’s age. Ten years ago he was five times his son’s age. Aman and his son's present ages are 60 and 20 years respectively.
☛ Related Questions:
- Amina thinks of a number and subtracts 5/2 from it. She multiplies the result by 8. The result now obtained is 3 times the same number she thought of. What is the number?
- A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the other new number. What are the numbers?
- Sum of the digits of a two-digit number is 9. When we interchange the digits, it is found that the resulting new number is greater than the original number by 27. What is the two-digit number?
- One of the two digits of a two-digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?
Math worksheets and
visual curriculum
visual curriculum