Altitudes MN and MO of parallelogram MGHK are 8 cm and 4 cm long respectively (Fig. 9.40). One side of GH is 6 cm long. Find the perimeter of MGHK.
Solution:
Given, MGHK is a parallelogram
The altitudes MN and MO of parallelogram are 8 cm and 4 cm
The length of one side GH is 6 cm.
We have to find the perimeter of MGHK.
Area of parallelogram = base × corresponding height
= GH × MN
= 6 × 8
= 48 cm²
Now, taking base HK and altitude MO
Area of parallelogram = HK × MO
48 = HK × 4
HK = 48/4
HK = 12 cm
Perimeter of parallelogram = 2(length + breadth)
Perimeter of parallelogram MGHK = 2(GH + HK)
= 2(6 + 12)
= 2(18)
= 36 cm
Therefore, the perimeter of the parallelogram is 36 cm.
✦ Try This: The perimeter of a rhombus is 160 cm and one diagonal is 10 cm long then the length of the other diagonal is
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 11
NCERT Exemplar Class 7 Maths Chapter 9 Problem 86
Altitudes MN and MO of parallelogram MGHK are 8 cm and 4 cm long respectively (Fig. 9.40). One side of GH is 6 cm long. Find the perimeter of MGHK.
Summary:
Altitudes MN and MO of parallelogram MGHK are 8 cm and 4 cm long respectively (Fig. 9.40). One side of GH is 6 cm long. The perimeter of MGHK is 36 cm
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