Add: 3a (a - b + c), 2b (a - b + c)

Solution:

Given terms to add → 3a (a - b + c), 2b (a - b + c)

⇒ 3a (a - b + c) + 2b (a - b + c)

= 3a² -3ab + 3ac + 2ab - 2b² + 2bc

= 3a² -ab + 2bc + 3ac - 2b²

✦ Try This: Add : 2x(x - 2y + 3z) , 5y(x + y + z)

Given, add 2x(x - 2y + 3z) , 5y(x + y + z)

⇒ [2x(x - 2y + 3z)] + [5y(x + y + z)]

= 2x² - 4xy + 6xz + 5xy + 5y² + 5yz

= 2x² + 5y² - 4xy + 5xy + 5yz + 6xz

= 2x² + 5y² + xy + 5yz + 6xz

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 81(vi)

Add: 3a (a - b + c), 2b (a - b + c)

Summary:

Adding 3a (a - b + c), 2b (a - b + c) we get 3a² -ab + 2bc + 3ac - 2b²

☛ Related Questions:

• Add: 3a (2b + 5c), 3c (2a + 2b)
• Subtract: 5a²b²c² from -7a²b²c²
• Subtract: 6x² - 4xy + 5y² from 8y² + 6xy - 3x²