Add: 3a (2b + 5c), 3c (2a + 2b)

Solution:

Given terms to add → 3a (2b + 5c), 3c (2a + 2b)

⇒ 3a (2b + 5c) + 3c (2a + 2b)

= 6ab + 15ca + 6ca + 6bc

= 6ab + 6bc + 21ca

✦ Try This: Add: 5x(x - y) , 5y(3x + 4y)

Given, add5x(x - y) , 5y(3x + 4y)

⇒ 5x(x - y) + 5y(3x + 4y)

= 5x² - 5xy + 15xy + 20y²

= 5x² + 10xy + 20y²

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 81(vii)

Add: 3a (2b + 5c), 3c (2a + 2b)

Summary:

Adding 3a (2b + 5c), 3c (2a + 2b) we get 6ab + 6bc + 21ca

☛ Related Questions:

• Subtract: 5a²b²c² from -7a²b²c²
• Subtract: 6x² - 4xy + 5y² from 8y² + 6xy - 3x²
• Subtract: 2ab²c² + 4a²b²c - 5a²bc² from -10a²b²c + 4ab²c² + 2a²bc²