Actual capacity of a vessel as shown in the Fig. 12.6 is equal to the difference of volume of the cylinder and volume of the hemisphere. Write ‘True’ or ‘False’ and justify your answer
Solution:
From the figure,
Actual capacity = Volume of cylinder - Volume of hemisphere
= πr²h - 2/3 πr³
Taking out the common terms
= πr²/3 (3h - 2r) cm³
Therefore, the statement is true.
✦ Try This: 50 circular plates each of diameter 14 cm and thickness 0.5 cm are placed one above the other to form a right circular cylinder. Find its total surface area.
It is given that,
Diameter of 50 circular plates = 14 cm
Radius of circular plates = 14/2 = 7cm
Thickness of plates = 0.5 cm
The total thickness of all the plates as it is placed one above the other = 0.5 x 50 = 25 cm
Total surface area of the right circular cylinder = 2πr × h + 2πr2
= 2πr (h + r)
Substituting the values
= 2(22/7) × 7 × (25 + 7)
So we get
= 2 × 22 × 32
= 1408 cm²
Therefore, the total surface area of the cylinder is 1408 cm².
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 13
NCERT Exemplar Class 10 Maths Exercise 12.2 Sample Problem 5
Actual capacity of a vessel as shown in the Fig. 12.6 is equal to the difference of volume of the cylinder and volume of the hemisphere. Write ‘True’ or ‘False’ and justify your answer
Summary:
The statement “Actual capacity of a vessel as shown in the Fig. 12.6 is equal to the difference of volume of the cylinder and volume of the hemisphere” is true
☛ Related Questions:
- Two identical solid hemispheres of equal base radius r cm are stuck together along their bases. The . . . .
- A solid cylinder of radius r and height h is placed over another cylinder of same height and radius. . . . .
- A solid cone of radius r and height h is placed over a solid cylinder having same base radius and he . . . .
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