ABCD is a trapezium in which AB||DC and P and Q are points on AD and BC, respectively such that PQ||DC. If PD = 18 cm, BQ = 35 cm and QC = 15 cm, find AD
Solution:
Given, ABCD is a trapezium in which AB||DC
P and Q are the points on AD and BC such that PQ||DC
We have to find the length of AD.
Given, PD = 18 cm
BQ = 35 cm
QC = 15cm
Also, AB||PQ||DC
Basic Proportionality Theorem states that if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio.
In △ABD,
Given, AB||PQ
So, PO||AB
By BPT, DP/AP = OD/OB -------------- (1)
In △BDC,
Given, DC||PQ
So, OQ||DC
By BPT, OB/OD = BQ/QC
On rearranging,
OD/OB = QC/BQ --------------------------- (2)
Equating (1) and (2),
DP/AP = QC/BQ
So, 18/AP = 15/35
AP(15) = 35(18)
AP = 7(18)/3
AP = 42 cm
We know, AD = DP + AP
AD = 18 + 42
AD = 60 cm
Therefore, the length of AD is 60 cm.
✦ Try This: In trapezium ABCD, AB||DC and L is the mid-point of BC. Through L, a line PQ||AD has been drawn which meets AB in P and DC produced in Q. Prove that ar (ABCD) = ar (APQD)
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 6
NCERT Exemplar Class 10 Maths Exercise 6.3 Problem 9
ABCD is a trapezium in which AB||DC and P and Q are points on AD and BC, respectively such that PQ||DC. If PD = 18 cm, BQ = 35 cm and QC = 15 cm, find AD
Summary:
ABCD is a trapezium in which AB||DC and P and Q are points on AD and BC, respectively such that PQ||DC. If PD = 18 cm, BQ = 35 cm and QC = 15 cm, then AD = 60 cm
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