ABCD is a parallelogram with vertices A (x₁ , y₁), B (x₂ , y₂) and C (x₃ , y₃). Find the coordinates of the fourth vertex D in terms of x₁, x₂, x₃, y₁, y₂ and y₃
Solution:
Given, ABCD is a parallelogram with vertices A (x₁ , y₁), B (x₂ , y₂) and C (x₃ , y₃).
We have to find the fourth vertex D in terms of x₁, x₂, x₃, y₁, y₂ and y₃.
We know that the diagonals of the parallelogram bisect each other.
So, midpoint of AC = midpoint of BD
The coordinates of the mid-point of the line segment joining the points P (x₁ , y₁) and Q (x₂ , y₂) are [(x₁ + x₂)/2, (y₁ + y₂)/2]
Midpoint of A(x₁ , y₁) and C(x₃ , y₃) = [(x₁ + x₃)/2, (y₁ + y₃)/2]
Let the coordinates of D be (x, y).
Midpoint of B(x₂ , y₂) and D(x, y) = [(x₂ + x)/2, (y₂ + y)/2]
Now, [(x₁ + x₃)/2, (y₁ + y₃)/2] = [(x₂ + x)/2, (y₂ + y)/2]
So, (x₁ + x₃)/2 = (x₂ + x)/2
Canceling out common terms,
x₁ + x₃ = x₂ + x
So, x = x₁ + x₃ - x₂
Also, (y₁ + y₃)/2 = (y₂ + y)/2
Canceling out common terms,
y₁ + y₃ = y₂ + x
So, y = y₁ + y₃ - y₂
Therefore, the coordinates of D are (x₁ + x₃ - x₂, y₁ + y₃ - y₂).
✦ Try This: The three vertices of a parallelogram taken in order are (-1, 0), (3, 1) and (2, 2) respectively.Find the coordinates of the fourth vertex.
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 7
NCERT Exemplar Class 10 Maths Exercise 7.3 Sample Problem 4
ABCD is a parallelogram with vertices A (x₁ , y₁), B (x₂ , y₂) and C (x₃ , y₃). Find the coordinates of the fourth vertex D in terms of x₁, x₂, x₃, y₁, y₂ and y₃
Summary:
ABCD is a parallelogram with vertices A (x₁ , y₁), B (x₂ , y₂) and C (x₃ , y₃). The coordinates of the fourth vertex D in terms of x₁, x₂, x₃, y₁, y₂ and y₃ are (x₁ + x₃ - x₂, y₁ + y₃ - y₂)
☛ Related Questions:
- If the mid-point of the line segment joining the points A (3, 4) and B (k, 6) is P (x, y) and x + y . . . .
- Find the area of the triangle ABC with A (1, –4) and the mid-points of sides through A being (2, – 1 . . . .
- Name the type of triangle PQR formed by the points P (√2, √2), Q (-√2, -√2) and R (-√6, √6)
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