A suitcase with measures 80 cm × 48 cm × 24 cm is to be covered with a tarpaulin cloth. How many meters of tarpaulin of width 96 cm is required to cover 100 such suitcases?

Solution:

Let the length of the tarpaulin cloth = x cm

Since, the suitcase is cuboidal in shape,

Total surface of the suitcase = 2(lb + bh + hl) .... (1)

Here, l = 80cm, b = 48cm, h = 24cm

Thus, substituting the values in equation (1) we get,

= 2 [(80 × 48) + (48 × 24) + (24 × 80)] cm²

= 2 [3840 + 1152 + 1920] cm²

= 13824 cm²

Total surface area of 100 suitcases

= 100 × 13824 m²

= 1382400 cm²

Area of the tarpaulin cloth required = Total surface area of 100 suitcases = 1382400 cm²

Area of the required tarpaulin cloth = Length × Breadth

1382400 cm² = x × 96 cm

x = 1382400/96 cm = 14400 cm

x = 144 m

Thus, the length of the tarpaulin cloth required is 144 m.

☛ Check: NCERT Solutions for Class 8 Maths Chapter 11

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Video Solution:

A suitcase with measures 80 cm × 48 cm × 24 cm is to be covered with a tarpaulin cloth. How many meters of tarpaulin of width 96 cm is required to cover 100 such suitcases?

Maths NCERT Solutions Class 8 Chapter 11 Exercise 11.3 Question 2

Summary:

A suitcase with measures 80 cm × 48 cm × 24 cm is to be covered with a tarpaulin cloth. 144 m of tarpaulin cloth is required to cover 100 suitcases of width 96 cm.

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